Question

sovle for x..........​

Answer 1

Answer:

Step-by-step explanation:

Hello mate!!

x2+5x−(a2+a−6)=0

⇒x2+5x−(a2+3a−2a−6)=0

⇒x2+5x−(a(a+3)−2(a+3))=0

⇒x2+5x−(a+3)(a−2)=0

⇒x2+[(a+3)−(a−2)]x−(a+3)(a−2)=0

⇒x2+(a+3)x−(a−2)x−(a+3)(a−2)=0

⇒x[x+(a+3)]−(a−2)[x+(a+3)]=0

⇒[x+(a+3)][x−(a−2)]=0

⇒[x+(a+3)]=0 or [x−(a−2)]=0

⇒x=−(a+3) or x=(a−2)

Hope it helps.

Do mark as brainliest!!