Question

sovle: x+2/6-(11-x/3-1/4)=3x-4/12 ?
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Answer 1

I think that it may help you.

Answer 2

Given :-

• $\mathsf{ \dfrac{x + 2}{6} - \bigg(\dfrac{11 - x}{3} - \dfrac{1}{4}\bigg) = \dfrac{3x - 4}{12}}$

To Find :-

• Value of x

Solution :-

$\mathsf\pink{{\: \: \: \: \: \: \: :\implies\dfrac{x + 2}{6} - \bigg(\dfrac{11 - x}{3} - \dfrac{1}{4}\bigg) = \dfrac{3x - 4}{12}}}$

$\mathsf{\: \: \: \: \: \: \: :\implies \dfrac{x + 2}{6} - \bigg(\dfrac{4(11 - x) - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: :\implies \dfrac{x + 2}{6} - \bigg(\dfrac{44 - 4x - 3}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: :\implies \dfrac{x + 2}{6} - \bigg(\dfrac{41 - 4x}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: :\implies \bigg(\dfrac{x + 2}{6} - \dfrac{(41 - 4x)}{12}\bigg) = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: :\implies \dfrac{2(x + 2) - (41 - 4x)}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: \: :\implies \dfrac{2x + 4 - 41 + 4x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: \: :\implies \dfrac{-37 + 6x}{12} = \dfrac{3x - 4}{12}}$

$\mathsf{\: \: \: \: \: \: \: \: :\implies {-37 + 6x} = {3x - 4}}$

$\mathsf{\: \: \: \: \: \: \: \: :\implies 6x - 3x = 37 - 4}$

$\mathsf{ \: \: \: \: \: \: \: \: :\implies 3x = 33}$

$\mathsf{\: \: \: \: \: \: \: \: :\implies x = \cancel{\dfrac{33}{3}}}$

$\sf \: \: \: \: \: \: \: \: \: \:\::\implies{\underline{\boxed{\frak{\pink{x =11}}}}}\:\bigstar$

$\therefore\:\underline{\textsf{ Value of x is \textbf{11}}}.$