Question

SP3 hybridization in Ammonia gives it to shape​

Answer 1

Answer:

If we look at the atomic number of nitrogen it is 7 and if we consider its ground state it is given as 1s², 2s²,2p³

$1s², \: \: \: \: 2s², \: \: \: \: \: \: \: \: \: \: \: \: \: 2p_x¹ 2p_y¹ 2p_z¹</p><p>$

$\boxed{↑↓}, \: \: \: \boxed{↑↓}, \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{↑}\boxed{↑}\boxed{↑}$

During the formation of ammonia, one 2s orbital and three 2p orbitals of nitrogen combine to form four hybrid orbitals having equivalent energy which is then considered as an sp3 type of hybridization.

Further, if we look at the NH3 molecule, you will notice that the three half-filled sp3 orbitals of nitrogen form bonds to hydrogen’s three atoms. However, the fourth sp3 orbital that is present is a nonbonding pair of hybridized orbital and is normally used for holding the lone pair.

molecular geometry of ammonia it has a trigonal pyramidal or distorted tetrahedral structure.

The bond angle in ammonia is less than the standard 109.5°.The bond angle is 107°.