Question

sp3 hybridization is not present in H2O or NH3 or CH4 or C2H4​

Answer 1

Solution :

• $\boxed{\red{\sf{H_2O}}}$

✏ $\sf{H_2O}$ has 2-Bond pair and 2-Lone pair.

✏ Total pairs = 2 + 2 = 4

✏ Hybridisation = $\sf{SP^3}$

• $\boxed{\sf\blue{NH_3}}$

✏ $\sf{NH_3}$ has 3-Bond pair and 1-Lone pair.

✏ Total pairs = 3 + 1 = 4

✏ Hybridisation = $\sf{SP^3}$

• $\boxed{\sf\green{CH_4}}$

✏ $\sf{CH_4}$ has 4-Bond pairs.

✏ Total pairs = 4

✏ Hybridisation = $\sf{SP^3}$

• $\boxed{\sf\orange{C_2H_4}}$

✏ $\sf{C_2H_4}$ has 3-Bond pairs.

✏ Total pairs = 3

✏ Hybridisation = $\sf{SP^2}$