Spam = 30 answers report
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Given: D and E are mid points of AB and BC respectively.
DF∥BC
Since, DF∥BC D is mid point of AB.
By converse of mid point theorem, F is mid point of AC.
Now, E and F are mid points of BC and AC respectively.Thus, by mid point theorem,
EF∥AB or EF∥DB
Since, opposite sides are parallel to each other. Hence, DBEF is a parallelogram.
given AF=3.2 cm
since F is midpoint then AF=CF=AC/2
AC=AF×2
then AC=2×3.2=6.4
Spam=30 answers reported
right answer=30 thanks ;-)
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