Math, asked by oObrainlyreporterOo, 1 month ago

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QUESTION: A cubical box has one of its sides as (2a - b) centimetres. What will be the volume of the box if we don’t consider the thickness of the walls of the box? If the box has to be painted outside on all the sides, what will be the surface area to be painted?​

Answers

Answered by loverofur15
1

Answer:

Length of side of a cubical box = (2a - b) cm

Note : Each and every side of a cube are equal to each other

Warning : Ignore thickness of the walls of cubical box

Volume of a cube (V) = (side)³

➠ V = (2a - b)³

(a - b)³ = a³ - b³ - 3ab(a-b)

➠ V = (2a)³ - b³ - 3(2a)b(2a-b)

➠ V = 8a³ - b³ - 12a²b - 6ab²

➠ V = 8a³ - b³ - 6ab(2a - b) cm³ \pink{\bigstar}★

The box has to be painted outside on all the sides , so it will covers total surface area of the cube .

Total Surface Area of the cube (TSA) = 6 (side)²

➠ TSA = 6 (2a - b)²

(a - b)² = a² + b² - 2ab

➠ TSA = 6 [(2a)² + b² - 2(2a)(b)]

➠ TSA = 6 [4a² + b² - 4ab]

➠ TSA = 24a² + 6b² - 24ab cm² \orange{\bigstar}★

Answered by khushikhan692
1

Answer:

Length of side of a cubical box = (2a - b) cm

Note : Each and every side of a cube are equal to each other

Warning : Ignore thickness of the walls of cubical box

Volume of a cube (V) = (side)³

➠ V = (2a - b)³

(a - b)³ = a³ - b³ - 3ab(a-b)

➠ V = (2a)³ - b³ - 3(2a)b(2a-b)

➠ V = 8a³ - b³ - 12a²b - 6ab²

➠ V = 8a³ - b³ - 6ab(2a - b) cm³ \pink{\bigstar}★

The box has to be painted outside on all the sides , so it will covers total surface area of the cube .

Total Surface Area of the cube (TSA) = 6 (side)²

➠ TSA = 6 (2a - b)²

(a - b)² = a² + b² - 2ab

➠ TSA = 6 [(2a)² + b² - 2(2a)(b)]

➠ TSA = 6 [4a² + b² - 4ab]

➠ TSA = 24a² + 6b² - 24ab cm² \orange{\bigstar}★

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