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Answered by s13397adisha2258
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Answer:

Answer

1x =a ² +b ² − a ² −b²

a 2 +b ²+ a² −b²

⇒ x−1x+1 = a 2+b 2 + a

2 −b ² − a 2 +b² + a ² −b²a ² +b ² + a ²−b ²+ a ² +b ² − a ² −b²

⇒ x−1x+1 = a ² −b ²a ² +b ²

⇒( x−1x+1 ) 2 = a ² −b ²a ²+b ²

⇒(x+1) 2 (a ² −b ² )=(a ² +b ² )(x−1) ²

⇒(x ² +1+2x)(a 2 −b² )=(x ²+1−2x)+(a 2 +b ²)

⇒x ² a ²−x ²b ² +a ²−b ² +2xa 2−2xb =x ²a²+x² b²+a ² +b²

−2xa 2 −2xb ²

⇒4xa ² =2x ² b ² +2b ²

⇒2xa ² =(x² b²+b2)

⇒b² (x 2 +1)=2xa²

⇒b² = x² +1 / 2xa² .

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