Math, asked by Dreamboi, 10 months ago

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Answered by Anonymous
3

Answer:

question :-

ABCD is a rhombus .Show that diagonal AC bisects angle A as well as angle C and diagonal BD bisects angle B as well as angle D

solution :-

given :-

ABCD is a rhombus so, it's all side are equal.

to prove :-

AC bisect angle A and angle C

BD bisect angle B and angle D

proof :-

Take a triangle ABC

in which AB=AC

AngleACB=AngleBAC. ----------------(Equation 1)

In triangle ADC

AD=CD

so, angle DCA=Angle DAC--------------(Equation2)

from 1 and 2

we get,

AC bisect angle A and angle B

similarly,

BD bisect angle C and angle D

Answered by Anonymous
1

Step-by-step explanation:

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ABCD is a rhombus

so, it's all side are equal.

Take a triangle ABC

in which AB=AC

AngleACB=AngleBAC. Equation 1

In triangle ADC

AD=CD

so, angle DCA=Angle DAC. Equation2

from 1 and 2

we get,

AC bisect angle A and angle B

similarly,

BD bisect angle C and angle D

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