Question

Spanner is used to open a nut a force of 15 n is applied to end of the spanner which is 20 CM away from the centre of the nut find out the movement when the scanner is parallel.​

Answer 1

Answer:

moment of force= force×distance

= 15× .2

= 3 Nm

Answer 2

$\huge \bold{ \red{ \underline{Given}}}$

Force = 15 N

Perpenducular distance = 20cm = 20 ÷ 100 = 0.2m

$\huge \bold{ \color{blue}{ \underline{To \: find}}}$

Movememt when spaner is parallel.

$\huge \bold{ \color{cyan}{ \underline{Solution }}}$

Movement = 15 × 0.20

= 3 Nm

$\fcolorbox{red}{lime}{Formula used here is m = f \: × d}$