Question

Specie 'X' with mass number 37 contains 11.1% more neutrons as compared to electrons,what is the INCORRECT representation of specie 'X'?? (A)37,17Cl- (B)37,17Cl (C)35,17Cl- (D)35,17Cl​

Answer 1

Solution with explanation :

Let 'x' be the number of electrons.

The number of neutrons are:

x + 0.111x = 1.111x

The number of protons is ' x - 1'.

The mass number is 37.

It is equal to the sum of the number of protons and the number of neutrons.

x - 1 + 1.111x = 37

=> 2.111x = 37 + 1

=> 2.111x = 38

=> x = 38 / 2.111

=> x = 18.000947

* Here, 18.000947 is rounded up to 18.

The number of electrons are 18.

The number of protons are 17.

Hence, the symbol of the ions is ( 37,17Cl- ) .

Thus, the incorrect representation of specie 'X' are:

(B)37,17Cl

(C)35,17Cl-

(D)35,17Cl

Answer 2

Answer:

The INCORRECT representation of Specie's' are :- B,C,D

Explanation:

Since mass number is 37

Options (c ) ,(d) are not possible

Now , according to option (A) and (b)

No. of neutrons = 20 .

No of e − = 20/1.111

                = 18

∴Hence species is 17 ^ ( 37 )cl −

#SPJ2