Question

Specific conductance of 0.01 N solution of an electrolyte is 0.00419 mho cm-! The equivalence conductance is:

419 mho cm-1

4.19 mho cm-1

0.00419 mho cm-1

None of these​

Answer 1

Answer:

The equivalence conductance is 419 mho-cm².

Explanation:

The equivalent conductance is defined as the net conductance of every ion that is produced from one gram equivalent of a given substance. It is calculated as,

$\wedge_e_q=\frac{k\times 1000}{N}$        (1)

∧eq=equivalent conductance

k=specific conductance of an electrolyte

N=normality of the solution

From the question we have,

N=0.01

k=0.00419=4.19×10⁻³mho cm⁻¹

By substituting the value of N and k in equation (1) we get;

$\wedge_e_q=\frac{4.19\times 10^-^3\times 1000}{0.01}=4.19\times 10^2=419mho -cm^2$

Hence, the equivalence conductance is 419 mho-cm².