specific conductance of 5 N solution is 0.01287 ohm-1 cm-1
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20
Hi..
relation between equivalent conductance and specific conductivity is as follows:
λ=κ x 1000N, where λ=Equivalent conductance, κ=specific conductivity, N= normalityPutting the given values into the equation,Equivalent conductance =λ=0.01287x10000.5=25.74 Ohm^-1cm^-1..
Hope this helps u!!
relation between equivalent conductance and specific conductivity is as follows:
λ=κ x 1000N, where λ=Equivalent conductance, κ=specific conductivity, N= normalityPutting the given values into the equation,Equivalent conductance =λ=0.01287x10000.5=25.74 Ohm^-1cm^-1..
Hope this helps u!!
Answered by
8
the answer is right well doing 25.74
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