Question

Specific conductance of saturated solution of AgCl is 2.68×10−4Sm−1 and that of water is 0.86×10−4Sm−1 at 298K. Calculate the solubility product in mol/dm3 unit if λm for HNO3​,AgNO3​ and HCl are 421×10−4Sm2 mol 133×10−4Sm2 mol,426×10−4Sm2 mol−1 respectively​

Answer 1

Answer:

Calculate the solubility product in mol/dm3 unit if λmo for HNO3, AgNO3 and HCl are 421 ... solubility of AgCl =(1.22×10−5)(143.5g/mol $$).