Specific conductivity of 0.01 N H,SO, solution is 6 * 10
S cm
Its molar conductivity is
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Answer: The molar conductivity of the given solution will be
Explanation: To calculate the molar conductivity of the solution, we use the formula:
......(1)
where, = Specific conductivity
c = concentration of the solution
We are provided with the normality of which is 0.01N.
To calculate the molar conductivity, we need the molarity of the solution. So, to convert normality into molarity, we use the formula:
where, n = acidity for basic solutions and basicity for acidic solutions
For , value of n = 2
Putting the values in above equation, we get
Given:
Putting values in above equation, we get
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