Question

Specific conductivity of 0.01 n h2so4 solution is .0006 s/cm. its molar conductivity

Answer 1

Answer: The molar conductivity of the given solution will be $120Scm^{-1}$

Explanation: To calculate the molar conductivity of the solution, we use the formula:

$\lambda _m=\frac{1000\times \kappa }{c}$   ......(1)

where, $\kappa$ = Specific conductivity

c = concentration of the solution

We are provided with the normality of $H_2SO_4$ which is 0.01N.

To calculate the molar conductivity, we need the molarity of the solution. So, to convert normality into molarity, we use the formula:

$Normality=n\times Molartiy$

where, n = acidity for basic solutions and basicity for acidic solutions

For $H_2SO_4$, value of n = 2

Putting the values in above equation, we get

$0.01=2\times Molarity$

$Molarity=0.005=5\times 10^{-3}M$

Given:

$\kappa =6\times 10^{-4}Scm^{-1}$

Putting values in above equation, we get

$\lambda _m=\frac{1000\times (6\times 10^{-4})}{5\times 10^{-3}}$

$\lambda _m=120Scm^{-1}$

Answer 2

Answer:

the answer should be 1200