Question

Specific conductivity of 0.01nh2so4 solution is 6×10-3 scm-1 it molar conductivity is

Answer 1

Explanation:

The relationship between specefic conductivity (K) and molar conductivity

Ʌm is as follows.

Ʌm=  K/c

Here c is the concentration in terms of molarity.

First of all we should find molarity. To do this multiply no. of replacable hydrogens with normality i.e. 0.01/2=0.005M

Now apply formula:

Ʌm=6×10-3/0.005=1.2 Scm-1M-1

Now to convert the units to Scm-2mol-1 multiply with 1000, the answer is 1200

You can check the calculation yoursel