Question

Specific gravity of silver is 11 and specific gravity of iron is 8.Which one among the following is the approximate relative density of silver with respect to iron
a.1.4
b.0.7
c.3.0
d.2.8

Answer 1

Answer:

1.4

Explanation:

Given - a) specific gravity of silver = 11

           b) specific gravity of iron =  8

To find - relative density of silver w.r.t iron

Solution - specific gravity = relative density w..r.t water at 4 degree celsius

∴ specific gravity = density of substance /density of water at  4 degree celsius

s.p 1 = density of silver /density of water = 11 ---------------------equation 1

let density of silver = x

and density of water = y

∴ x = 11y

similarly ⇒ let density of iron = z

so s.p 2 = density of iron /density of water = 8

z = 8y ---------------------------equation 2

now relative density of substance = density of A/density of B

∴ relative density of silver w.r.t iron = x/z ⇒ 11y/8y = 11:8

1.375 ~ 1.4

Answer 2

Answer:

Relative density of silver with respect to iron is option(a) 1.4

Explanation:

Given: Specific Specific gravity of silver is 11

Specific gravity of iron is 8.

To Find: Relative density of silver with respect to iron

Step Wise Solution: Specific gravity for a substance can be described as relative density of a solution with respect to water at a particular temperature(4 degree Celsius).

Therefore, specific gravity = density of substance /density of water

Specific density of silver = density of silver/density of water = 11

Let density of silver = x and density of water = y

So, x/y = 11   ∴ x = 11y

Similarly, Let density of iron = z

So specific density of iron = density of iron /density of water = 8

z/y = 8   ∴ z = 8y

Now relative density of substance = density of substance1/density of substance2

Relative density of silver with respect to iron = x/z = 11y/8y = 11/8 = 1.3752 which can be written as 1.4.

So, relative density of silver with respect to iron is 1.4.

Code:SPJ2