Question

Specific heat of mercury is 0.03 cal/gm°C. Its value in S.I is
Explain then no joke​

Answer 1

Heat is required for two purposes:

1) To raise the temperature of the liquid at 22^o C till its boiling point.

2) To convert the liquid at its boiling point into vapour.

For mercury:

H_1=m*s*(t_2-t_1)

=1*0.03*(357-22)

=1*0.03*335

=10.05 cal

H_2 =latent heat*mass

=65*1=65 cal

Hence, H=H_1+H_2

=(10.05+65)=75.05 cal

For water:

H_1=m*s*(t_2-t_1)

=1*1*(100-22)

=78 cal

H_2 =latent heat*mass

=540*1=540 cal

Hence, H=H_1+H_2

=(78+540)=618 cal

Therefore, it takes more energy to boil a gram of water than to boil a gram of mercury.

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