Question

Specify the oxidation numbers of the metals in the following coordination entities: (i) [Co(H2O)(CN)(en)2]2+ (ii) [CoBr2(en)2]+ (iii) [PtCl4]2− (iv) K3[Fe(CN)6] (v) [Cr(NH3)3Cl3]

Answer 1

1] 3+

2] 3+

3] 2+

4]3+

5]3+

Answer 2

Explanation:

A free element's oxidation number is always0. A monatomic ion's oxidation number is equal to the ion's charge. The amount of H oxidation is+ 1, but in combination with fewer electronegative components it is-1. In compounds, the oxidation number of O is generally-2, but in peroxides it is-1.

The oxidation for the following equations will be -

(i) [Co(H2O)(CN)(en)2]2+  --- 3

(ii) [CoBr2(en)2]+ --- 3

(iii) [PtCl4]2− --- 2

(iv) K3[Fe(CN)6] --- 3

v) [Cr(NH3)3Cl3] --- 3