Question

Spectral line of an element have a wavelength of 455 nm. Calculate its wave no. and frequency.
from 11 class

Answer 1

Heya !!

Here's your answer...

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Given :- Wavelength of an element is 455 nm.

To find :- ( i ) It's frequency and ( ii ) Wave no.

Salutation :-

( i ) Frequency = Velocity / Wavelength

= ( 3 × 10^8 ) m/s / ( 455 × 10^-9 ) m

= 6.5 × 10^14 Hz.

( ii ) Wave no = 1 / Wavelength

= 1 / 455 × 10^-9 m

= 2.197 × 10^6 m^-1


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Thanks!

Answer 2

In physics and chemistry, the Lyman series is a hydrogen spectral series of transitions and resulting ultraviolet emission lines of the hydrogen atom as an electron goes from n ≥ 2 to n = 1 (where n is the principal quantum number), the lowest energy level of the electron.