Question

speech can also be a cruse give examples to this​

Answer 1

Answer:

Given :-

Force applied to lift the box = 100 N

Height of the box = 10 m

To Find :-

The potential energy of an stored in the box.

Analysis :-

Here we are given with the mass and height of the box.

Firstly, using the formula of force (ie. force is equal to mass multiplied by the acceleration) find the acceleration accordingly.

In order to find the potential energy of the object substitute the values in the question such that potential energy mass into gravity into height and find the potential energy accordingly.

Solution :-

We know that,

m = Massh = HeightPE = Potential energyg = Gravitya = Accelerationf = Force

Using the formula,

\underline{\boxed{\sf Force=Mass \times Acceleration}}Force=Mass×Acceleration

Given that,

Force (f) = 100 N

Acceleration (a) = 10 m/s

Substituting their values,

⇒ f = ma

⇒ 100 = m × 10

⇒ m = f/a

⇒ m = 100/10

⇒ m = 10 kg

Using the formula,

\underline{\boxed{\sf Potential \ energy=Mass \times Gravity \times Height }}Potential energy=Mass×Gravity×Height

Given that,

Mass (m) = 10 kg

Gravity (g) = 10 m/s

Height (h) = 10 m

Substituting their values,

⇒ PE = mgh

⇒ PE = 10 × 10 × 10

⇒ PE = 1000 J

Therefore, the potential energy of an box is 1000 J.

Answer 2

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