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Explanation:
Correct Question:-
Haemoglobin contains 0.25% iron/weight the molecular mass of hemoglobin is 89600 calculate the no. of Iron (Fe) atoms present per molecule of hemoglobin??
Required Answer:-
Molecular mass of Haemoglobin = 89600
Percentage of Iron = 0.25% / weight. This means the total mass of Iron out of the total molecular mass of Haemoglobin is 0.25% of 89600.
GiveN mass of Iron:
= 0.25% × 89600
= 25/10000 × 89600
= 1/400 × 89600
= 224 gm of Iron.
Moles of Iron:
= Given Mass / Atomic mass
= 224 gm / 56 gm
= 4 moles.
Now here, 1 mole of Haemoglobin contains 4 moles of Iron (Fe). Then 1 molecule of Haemoglobin will have 4 atoms of Fe.
Hence:-
No. of Iron atoms present per molecule of hemoglobin = 4
Answer:
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