Question

speed of a car changes from 30 metre per second to 20 metre per second in 5 seconds calculate the acceleration and distance travelled by the car​

Answer 1

Given :-

$\sf\bullet { Initial \: Velocity\:(u)\:=\:30m/s}$

$\sf\bullet { Final\: Velocity\:(v)\:=\:20m/s}$

$\sf\bullet { Time(t)\:=\:5sec.}$

To find :-

$\sf\ { Acceleration}$

$\sf\ { Distance }$

Formula used !

$\bigstar{\boxed{\sf{ a \: =\: \frac{v-u}{t}}}}$

$\bigstar{\boxed{\sf{ S \: =\: ut+ \frac{at^2}{2}}}}$

$\huge{ \underline{ \pink{ \mathrm{Solution}}}}$

$\huge{ \mathrm{ \boxed{ \red{Acceleration}}}}$

$\begin{lgathered}⟹ \ a = \ \frac{v-u}{t} \\ \\⟹ \ a = \ \frac{20-30}{5} \\ \\⟹ \ a = \ \frac{-10}{5} \\ \\⟹ \ a = \ -2m/s^2\end{lgathered}$

$\huge{ \mathrm{ \underline{ \purple{\ a = \ -2 m/s^2}}}}$

$\huge{ \mathrm{ \boxed{ \red{Distance}}}}$

$\begin{lgathered}\ ⟹ S = \ ut+ \frac{at^2}{2} \\ \\⟹ \ S = \ 30×5+ \frac{(-2)(5^2)}{2} \\ \\⟹\ S = \ 150 - \frac{50}{2} \\ \\⟹\ S = \ 150 - 25 \\ \\⟹ \ S = \ 125m \end{lgathered}$

$\huge{ \mathrm{ \underline{ \purple{\ S = \ 125m}}}}$