Question

Speed of a car increases from 36 km/h to 90 km/h in 15 second find initial velocity and final velocity, acceleration and distance covered in 10 second

Answer 1

● INITIAL VELOCITY = U

=> U = 36 km/hr ________[Given]

=> U = 36 × 5/18 m/s

=> U = 10 m/s _________[Answer]

____________________________

● FINAL VELOCITY = V

=> V = 90 km/hr _________[Given]

=> V = 90 × 5/18 m/s

=> V = 25 m/s ___________[Answer]

______________________________

● TIME = t

=> t = 15 sec _________[Given]

______________________________

● ACCELERATION = a

$= > a \: = \frac{v - u}{t} \\ \\ = > a = \frac{25 - 10}{15} \\ \\ = > a \: = 1 \: \frac{m}{ {s}^{2} }$

=> a = 1 m/s² __________[Answer]

_____________________________

NOW,

DISTANCE travelled in 10 sec

● DISTANCE = s

$= > s \: = ut \: + \: \frac{1}{2} a {t}^{2} \\ \\ = > s \: = 10 \times 10 \: + \frac{1}{2} \times 1 \times {10}^{2} \\ \\ = > s \: = 100 + \frac{100}{2} \\ \\ = > s \: = 150 \: m$

=> S = 150 m __________[Answer]

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☆ $BE \: \: BRAINLY$ ☆