speed of a seconds hand of a watch in rad/s
Answers
Answered by
0
Answer:
The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater. The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds, so ω = π/30 rad.s-1 = 0.03 rad.s-1.
Answered by
0
The seconds hand of a clock completes one rotation in 1 minute i.e 60 seconds.
Angular speed=angle swept by the radius vector÷time taken
Angle swept for one complete rotation is 2π radians
Therefore, 2π/60=π/30
Answer: π/30 radians per second
Similar questions