Physics, asked by bareera8, 10 months ago

speed of a seconds hand of a watch in rad/s

Answers

Answered by aadityasinha2004
0

Answer:

The angular velocity is independent of the clock size, however for larger clocks the linear velocity of the pointers at the end of the hands will be greater. The second hand goes through 2π radians in 1 min, or 2π radian/60 seconds, so ω = π/30 rad.s-1 = 0.03 rad.s-1.

Answered by Anonymous
0

The seconds hand of a clock completes one rotation in 1 minute i.e 60 seconds.

Angular speed=angle swept by the radius vector÷time taken

Angle swept for one complete rotation is 2π radians

Therefore, 2π/60=π/30

Answer: π/30 radians per second

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