Speed of a ship is 8 kmph in still water. It goes downstream from point A to B. After travelling 1/2 of the distance the ship malfunctioned and travelled along the stream and reached point B taking 360 minutes more than the normal time. If the speed of the current is 2 kmph then what is the distance A and B in km?
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⇒ Let x be the speed of the stream.
⇒ Speed of the boat in still water is 8km/hr
⇒ The speed of the boat in upstream is 8−km/hr
⇒ The speed of the boat in downstream is 8+x km/hr
⇒ The time taken by the boat to cover 15km=
8−x15 hr
⇒ The time taken by the boat to cover 22km= 8+x22 hr
According to the question,
⇒ 8−x15 + 8+x22 =5
⇒ 15(8+x)+22(8−x)=5(8−x)(8+x)
⇒ 120+15x+176−22x=5(64−x 2 )
⇒ 296−7x=320−5x 2
⇒ 5x 2 −7x−24=0
⇒ 5x 2 −15x+8x−24=0
⇒ 5x(x−3)+8(x−3)=0
⇒ (x−3)(5x+8)=0
⇒ x−3=0 and 5x+8=0
⇒ x=3 and x=− 58
Speed cannot be negative.
∴ The speed of the stream is 3km/hr
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