Question

Speed of a train increases from 36km/h to 72km/h in 10 minutes. Find distance
covered by the train

Answer 1

Explanation:

36km/h = 36*5/18 m/s = 10m/s

72km/h = 72*5/18 m/s = 20m/s

a = (v - u)/t

a = (20 - 10)/10

a = 10/10

a = 1m/s^2

S = ut + 0.5at^2

S = 10*10 + 0.5*1*10^2

S = 100 + 50

S = 150m

Distance travelled during this time is 150m