Question

Speed of an object changes from 5 m/s to 9 m/s in 2 s, then its acceleration in SI unit will be *

3

4

1

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Answer 1

Understanding the question: This question says that we have to find out the acceleration in the SI unit if the speed of an object changes its velocity from 5 m/s to 9 m/s in 2 seconds. Let's do it!

Provided that:

• Initial velocity = 5 m/s
• Final velocity = 9 m/s
• Time taken = 2 seconds

To calculate:

• The acceleration

Solution:

• The acceleration = 2 m/s²

Using concept:

• Acceleration formula

Using formula:

• ${\sf{a \: = \dfrac{v-u}{t}}}$

Where, v denotes final velocity, u denotes initial velocity, t denotes time and a denotes acceleration.

Knowledge required:

• SI unit of a is m/s²

• That is because the SI unit of velocity is m/s and SI unit of time is seconds Therefore, when combined then it be m/s²

Full solution:

~ To solve this question we just have to use formula to find out acceleration and have to put the values, further solve!

$:\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{9-5}{2} \\ \\ :\implies \sf a \: = \dfrac{4}{2} \\ \\ :\implies \sf a \: = 2 \: m/s^2 \\ \\ :\implies \sf Acceleration \: = 2 \: m/s^2$

Answer 2

Explanation:

Here

• initial velocity=u=5m/s
• Final velocity=v=9m/s
• Time =t=2s

We have to find Acceleration.

We know that

$\boxed{\sf Acceleration(a)=\dfrac{v-u}{t}}$

$\\ \sf\hookrightarrow Acceleration=\dfrac{9-5}{2}$

$\\ \sf\hookrightarrow Acceleration=\dfrac{4}{2}$

$\\ \sf\hookrightarrow Acceleration= 2m/s^2$

Hence

option D is correct.