Question

speed of light in medium A and medium Bare 25 x 10^8 m/s and 2 x 10^8 m/s respectively then the refractive index of medium A with
um B will be?​

Answer 1

Answer:

2/25

Explanation:

Given :

• Speed of light in vaccum A = 25×10^8 m/s

• Speed of light in vaccum B = 2×10^8

To find :

• Refractive index of medium A with respect to medium B

Refractive index 1 = speed of light in vaccum / speed of light in medium A

Refractive index 1 = 3×10^8 / 25×10^8

Refractive index 2 = 3×10^8/ 2×10^8

Refractive index of medium 1 with respect to medium 2

= 3×10^8/25×10^8/3×10^8/2×10^8

= 3×10^8/25×10^8 × 2×10^8/3×10^8

= 2×10^8/25×10^8

= 2/25

The answer is equal to 2/25

Answer 2

Answer :

Given that speed of light in medium A is 25 × 10⁸ m/s and medium B is 2 × 10⁸ m/s

We have to find refractive index of medium A with B.

From there we get :

Speed in medium A = 25 × 10⁸ m/s

Speed in medium B = 2 × 10⁸ m/s

Speed of light in vaccum = 3 × 10⁸ m/s

Now we know,

→ Refractive index = Speed of light in vaccum/Speed of light in medium

→ Refractive index 1 = (3 × 10⁸)/(25 × 10⁸)

→ Refractive index 1 = 3/25

→ Refractive index 2 = (3 × 10⁸)/(2 × 10⁸)

→ Refractive index 2 = 3/2

Now refractive index of medium A with B :

→ Refractive index 1/Refractive index 2

→ (3/25)/(3/2)

→ (3/25) × (2/3)

→ 2/25

∴ Refractive index of medium A with medium B = 2/25