Question

speed of light in si system is 3 ×10^8 .In a new system unit of length is a km and unit of time is b second then speed of light in new system of unit is​

Answer 1

Answer:

3×10^5×b/a

Explanation:

Speed of Light in SI system = 3 × 10^8 m/sec

Light covers a distance of 3 × 10^8 m in 1 sec

Therefore,

It covers in 1 sec

$\frac{3 \times {10}^{8} }{a \times {10}^{3} } km$

Hence it covers

in b sec

$3 \times {10}^{5} \times \frac{b}{a}$

Answer 2

Answer:

The speed of light in new system of unit is​$\dfrac{3\times10^{5}b}{a}$.

Explanation:

Given that,

Speed of light in SI system =$3\times10^{8}\ m/s$

let the speed of light in new system is x units.

$3\times10^{8} m/s = x\ unit$

let L₁, T₁ and L₂, T₂ be the symbols of length and time in two systems.

$3\times10^{8}[L_{1}T_{1}^{-1}]=x[L_{2}T_{2}^{-1}]$

$x=\dfrac{3\times10^{8}[L_{1}T_{1}^{-1}]}{[L_{2}T_{2}^{-1}]}$

$x=\dfrac{3\times10^{8}L_{1}T_{1}^{-1}}{L_{2}T_{2}^{-1}}$

$x=\dfrac{3\times10^{8}b}{a\times10^{3}}$

$x=\dfrac{3\times10^{5}b}{a}$

Hence, The speed of light in new system of unit is​$\dfrac{3\times10^{5}b}{a}$.