Question

speed of light is 3×10^8m/s in vaccum what will be its speed in diamond of mirrage​

Answer 1

Explanation:

Refractive index of diamond = 2.4

Now,

$n = \frac{speed \: in \: vccum}{speed \: in \: diamond}$

Using this relation,

$2.4 = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{x}$

$x = 1.24 \times {10}^{8} \: m {s}^{ - 1}$