Question

speed of train increase from 36km/h to 72km/h in 10 minutes find distance covered by the train during this time

Answer 1

Answer:

first acceleration

v= 72 km/hr

u= 36km/hr

t= 10/60=1/6 hr

from formula v=u+at

72=36+a*(1/6)

72-36=a/6

36*6=a

a = 216 km/hr2

from equation V2= u2 +2as

(72)2= (36)2+2*216*s

5184= 1296+432S

5184-1296=432s

3888/432=S

S= 9 km