Question

speed of two cars are u and 4u at specific instant . the ratio of the respective distance in which the two cars are stopped from that instant is

Answer 1

Answer:

By Newtons third law of motion

V²-U²=2as

here the acceleration a is negative since it is retardation, displacement s is the stopping distance d, u is the initial velocity and v is the final velocity.

Since the objects stops after the motion, v=0

That is

 

   ⇒-u²= -2ad

d= u/2a

Lets take d1 as the distance traveled by the car with velocity U and d2 as the distance traveled by the car with velocity  4u.

The retardation for both the cars is -a

   ⇒d1/d2=U²/2a * 2a/4u²

   ⇒d1/d2= 1/16

Answer 2

Answer:

Explanation:this is ur answer