Physics, asked by kriti9382, 7 months ago

speed of two objects are u and 4u at specific instant . find the ratio of the respective distance at which the two objects stopped? Snth = u+(a/2)[2n-1]

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Answered by bowassathyavasan

Answer:

use your brain

Explanation:

good question

Answered by Anonymous

Answer:

speed of two objects are u and 4u at specific instant . find the ratio of the respective distance at which the two objects stopped? Snth = u+(a/2)[2n-1]

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speed of two objects are u and 4u at specific instant . find the ratio of the respective distance at which the two objects stopped? Snth = u+(a/2)[2n-1]​

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speed of two objects are u and 4u at specific instant . find the ratio of the respective distance at which the two objects stopped? Snth = u+(a/2)[2n-1]