Question

speed position relation of a particle moving in a straight line is given as vsquare equal to a minus bx square then acceleratio
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Answer 1

Answer:

The acceleration of the particle is proportional to ​x

Explanation:

The speed-position relation of a particle moving in a straight line is given asV square is equal to a minus b x square where A and B are constant.

The equation is given as:

V^2= a- bx^2 [ where A and B are constant]............ (i)

The acceleration of the particle is a

a = Vdv/dx

Derivation both side of (i) we get

2V dv/dx =-2 bx

V dv/dx = -bx

putting the value of a

a = -bx

Therefore a ∝ x