Math, asked by sumitdiwakar72, 7 hours ago

speedometer. Question:4) In one trip, Rajesh rode 4km in total journey of 10km in the first 10minutes and then 2km in next 5minutes. Which one is correct in the following A) Rajesh average speed was greater the first 10min than in next 5min B) than in Rajesh average speed was less than in the first 10 min than in next 5min c) Rajesh average speed was same in the first 10min and next 5min D) Not possible to tell


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Answers

Answered by chetanmv375
5

Answer:

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Step-by-step explanation:

Speed=

Time

Distance

⇒Distance=Speed×Time

So, distance to the school =12km/hr×20minutes=12km/hr×

60

20

hour=4 km

So, to cover distance 4km in 15minutes,

Speed=

15min

4km

=

(

60

15

)hour

4km

=16km/hr

Answered by PoojaBurra
0

Given: In one trip, Rajesh rode 4km in total journey of 10km in the first 10minutes and then 2km in next 5minutes.

To find: The correct option.

Solution:

The speed of a body is the distance travelled by it in unit time. It is given by the following formula.

s = \frac{d}{t}

Here, s is the speed, d is the distance travelled by Rajesh and t is the time period. Now, the speed of Rajesh for the first 10 minutes and the next 5 minutes can be calculated as follows.

s_{1} = \frac{4 km}{10 min}

    = 0.4 km/min

s_{2} = \frac{2 km}{5 min}

    = 0.4 km/min

As evident from the speeds calculated, the average speed of Rajesh was the same during the 10 minutes and the five minutes.

Therefore, the correct option is c) Rajesh average speed was same in the first 10min and next 5min.

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