Question

Spencer hits a tennis ball past his opponent. The height of the tennis ball, in feet, is modeled by the equation h(t) = –0.075t2 + 0.6t + 2.5, where t is the time since the tennis ball was hit, measured in seconds. How long does it take for the ball to reach the ground?

Answer 1

Answer:

t= 11.02 second

Step-by-step explanation: Dear Student,

Given,

$h(t)= -.075t^{2} +0.6t+2.5$

According to the question,when it will reach the ground

   h(t) = 0

$0= -.075t^{2} +0.6t+2.5$

$\frac{3}{40} t^{2} -\frac{6}{10}t-2.5 = 0$

$\frac{3}{40}t^{2}-\frac{6}{10}t-\frac{5}{2} =0   \\3t^{2}-24t-100=0$