Question

Sphere A of mass 2kg moving along a straight
line with a velocity of 10 m/s hits another sphere
'B' of mass 3kg which is at rest. If they stick
together and move with a common velocity
along the same straight line after collision, if the
collision lasted 0.1 second, the force exerted on
B during the impact will be
1) 12N 2) 1200n 3) 120N 4) 150N​

Answer 1

Answer:

150 N

Explanation:

Change in momentum is force so we have to calculate change in momentum

Here Momentum is conserved as no external force acting so

initial momentum of both particle = final momentum of both particle

2*10 + 3*0(rest) = 2*v + 3*v

20 = 5v

v = 4m/s

change in momentum of 3 kg sphere = initial momentum - final momentum

∆p = 0 - (-5*3). -ve because direction of velocity changes.

∆p = 15

accn = ∆p/∆t = 15/0.1 = 150 N