Question

spherical marble of radius 1 cm is stuck in a circular hole of radius slightly smaller than its own
calculation purpose, bon can be taken same) at the bottom of a bucket of height 40 cm and med
with water up to 10 cm. If the mass of
mas o ne marble is 20 9, the net force on the marble due to water is
A spherical marble
close to
(A) 0 02 N upwards
(B) 0.02 N downwards (C) 0.04 N upwards
(D) 0.04 N downwards
nrn hoth variable The graph of​

Answer 1

Answer:

0.02Nupwards

Explanation:

Radius of the marble =r=1cm=0.01m

Volume of marble =4/3πr^3

Volume of marble inside water =V=2/3πr^3

Volume water displaced =V=2/3πr^3

Density of water =D=1000kg/m3

Mass of water displaced =M=D∗V

=2/3Dπr^3

Weight of water displaced =W=Mg=2/3Dπr^3g

Net force =W=2/3Dπr^3g

=23×1000×3.14×(0.01)3×10=0.0209Nupwards≈0.02Nupwards