Question

spherical marbles of diameter 1.4cm are dropped into a cylindrical beaker of diameter 7cm which contains some water. find the number of marbles that should be dropped into the beaker so that water level rises by 5.6cm​

Answer 1

Answer:

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Diameter of the Spherical ball ( d ) = 1.4cm

radius of the ball ( r ) = d/2

r = 0.7 cm

Volume of the Sphere = ( 4/3 )πr³ cm³

v = ( 4/3 ) π ( 0.7 )³ ----( 1 )

ii ) Diameter of the cylinder ( D ) = 7cm

radius of the cylinder ( R ) = D/2

R = 7/2 cm

Suppose water level rises by h= 5.6 cm

in the cylindrical beaker .

Then ,

Volume of the cylinder of height

h = 5.6 cm and radius 7/2 cm

V = πR²h

V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 )

Let the number of balls dropped in the

beaker = n

n = V /v

n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³]

after cancellation ,we get

n = 150

Thank you.

Answer 2

Answer:

Spherical marble= 150

Step-by-step explanation:

here,

we have first supposed the number of marbles dropped be "n".

rest everything is clearly given in the attached pic.

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