Question

spiliting the middle term 6x^2 -x -2​

Answer 1

Factorise : $\sf 6x^2 - x - 2$

Find two numbers, such that their product is 12 and difference is 1.

• Here, 4 × 3 = 12
• 4 - 3 = 1

So,

split the middle term.

We get,

$\sf = 6x^2 - ( 4 - 3 ) x - 2$

$\sf = 6x^2 - 4x + 3x - 2$

$\sf = 2x ( 3x - 2 ) + 1 ( 3x - 2 )$

$\sf = ( 2x + 1 ) ( 3x - 2 )$

$\rule{200}2$

Answer 2

Answer:

Factorise : \sf 6x^2 - x - 26x2−x−2

Find two numbers, such that their product is 12 and difference is 1.

Here, 4 × 3 = 12

4 - 3 = 1

So,

split the middle term.

We get,

\sf = 6x^2 - ( 4 - 3 ) x - 2=6x2−(4−3)x−2

\sf = 6x^2 - 4x + 3x - 2=6x2−4x+3x−2

\sf = 2x ( 3x - 2 ) + 1 ( 3x - 2 )=2x(3x−2)+1(3x−2)

\sf = ( 2x + 1 ) ( 3x - 2 )=(2x+1)(3x−2)

$$\rule{200}2$$