Question

spiltting the middle term of x^2-14x+45=0​

Answer 1

Step-by-step explanation:

${x}^{2} - 14 + 45 = 0 \\ = {x}^{2} - 9x - 5x + 45 \\ = x (x - 9) - 5(x + 9) \\ = (x - 5)(x - 9) \: \: or \: (x - 5)(x + 9)$

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${x}^{2} - 14 + 45 = 0 \\ = {x}^{2} - 9x - 5x + 45 \\ = x (x - 9) - 5(x + 9) \\ = (x - 5)(x - 9) \: \: or \: (x - 5)(x + 9)$