Question

split 207 into 3 parts such that these are in AP and the product of two smaller part is 4623

Answer 1

Let no. S be a-d, a, a+d.
a-d+a+a+d=207
a=69
Given (a-d) ×a=4623by substituting values of a in it then we get d=2.
A.P is 69,71,73
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Answer 2

Answer:

Let the three parts of the number 207 are (a - d), a and (a + d), which are in AP.

Now, by given condition,

=> Sum of these parts = 207

=> a - d + a + a + d = 207

=> 3a = 207

⠀⠀a = 69

Given that, product of the two smaller parts = 4623

=> a(a - d) = 4623

=> 69.(69 - d) = 4623

=> 69 - d = 67

=> d = 69 - 67 = 2

So, first part = a - d = 69 - 2 = 67,

Second part = a = 69

and third part = a + d = 69 + 2 = 71

Hence, required three parts are 67, 69, 71.