split 207 into three parts such that these are in AP and the product of the two smaller parts is 4623.
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Let the numbers be (a−d),a,(a+d). Then,
Sum =207⇒(a−d)+a+(a+d)=207⇒3a=207⇒a=69
Product of two smaller parts =4623
⇒a(a−d)=4623⇒69(69−d)=4623⇒69−d=67⇒d=2
Thus the numbers are (69−2),69,(69+2)
i.e. 67,69,71
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