Math, asked by manojkumar26112004, 10 months ago

split 3y2+20y-63 by splitting the middle term.

Answers

Answered by rawonthangkhiew

1

Answer:

Step-by-step explanation:

here a=3 and c=63

Therefore ac=3×63=189

27-7=20, and 27×7=189

Therefore

3y^2+20y-63=0

3y^2+27y-7y-63=0

3y(y+9)-7(y+9)=0

(y+9)(3y-7)=0

Either

y+9=0 or 3y-7=0

Y=-9 or 3y=7

y=7/3

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