Question

Split 69 into 3 parts such that they are in a.p and a product of two smaller parts is 483.

Answer 1

Solution:-
Let the first term of the AP be 'a'
And the common difference be 'd'
Since 69 split into 3 parts such that they form an AP.
Let the three parts be (a - d), (a) and (a + d).
Therefore,
(a - d) + (a) + (a + d) = 69
3a = 69 
a = 23
The product if two smaller parts = 483
So, 
(a) × (a - d) = 483
23 × (23 - d) = 483
⇒ 529 - 23d = 483
⇒ - 23d = 483 - 529
⇒ - 23 d = - 46
⇒ d = 46/23
⇒ d = 2
Therefore,
The 3 parts are   
23 - 2 = 21 ;
23 
and 23 + 2 = 25
Hence the parts of the given AP are 21, 23, 25  
Answer.

Answer 2

Answer:

Hope it helps you!!!