split it and compare it with quadratic polynomial
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we can write it in the form of extander quadratic polynomial tha is..
ax sq + bx + c = 0
according to the question we have,
x sq + 0x - 4 = 0 ( at place of bx we can put 0x)
now splitting,
x sq + 0x - 4 = 0
x sq + 1x - 1x - 4 = 0
x(x+1) 1(x-1) - 4 = 0
(x+1) (x-1) = 0
x= -1 and x= +1 is the two zeroes of the polynomial.
hope it helps you...
ax sq + bx + c = 0
according to the question we have,
x sq + 0x - 4 = 0 ( at place of bx we can put 0x)
now splitting,
x sq + 0x - 4 = 0
x sq + 1x - 1x - 4 = 0
x(x+1) 1(x-1) - 4 = 0
(x+1) (x-1) = 0
x= -1 and x= +1 is the two zeroes of the polynomial.
hope it helps you...
hania97:
10 th class
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