Question

Split middle term in the following:-
$x {}^{2} - 64x - 130 = 0$
​

Answer 1

The given quadratic equation is taken as

p(x) = x²-64x-130

It is of the form ax²+bx+c

Where a=1 ; b=(-64) ; c=(-130)

b = -64 and ac = -130

Hence we need to find two numbers whose DIFFERENCE is 64 and PRODUCT (-130)

By trial and error we conclude that there are no such numbers that satisfy the above mentioned requirements

Hence we can't split the middle term appropriately