Math, asked by gunaramhembram470, 10 months ago

split the middle term​

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Answered by yashaswi66
0

3x^2-x-4

3x^2-4x+3x-4

x(3x-4)+1(3x-4)

(3x-4)(x+1).............Is ur answer!

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Hope it might helped u

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Answered by AdorableAstronaut
39

 \huge{ \underline{ \mathfrak{Answer :}}}

We Could solve this problem by the process called Splitting The Middle Term.

So, let's get to know a little about this.

Suppose, there's an equation = 6x² + 19x + 10

Let's solve this using Splitting The Middle Term's Process.

So first, you should find the product of first and last term. In our equation, the first term is 6x^2 and the last term is 10.

The product of 6x² and 10 is 60x².

Next step is to find the multiples of 60x²

One multiple is 15 × 4.

We should select the multiples such that when you add or subtract those multiples the given answer should be equal to the middle term given in the question.

Getting it?

Yea so, coming to the example :

60x² + 15x + 4x + 10.

Let's now take numbers common in the given example. You'll get -

3x ( 2x + 5 ) + 2 ( 2x + 5 )

(3x + 2) (2x + 5)

So that's the concept of Splitting The Middle Term.

Coming to your question :

  • 3x² - x - 4

4 × 3x² = 12x²

12x² = 3 × 4

3x² - 4x + 3x - 4.

x ( 3x - 4 ) + 1 ( 3x - 4 )

= ( 3x - 4 ) ( x + 1 )

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