Question

split the middle term and find the zeros for 2√2 x² - 9x + 5√2​

Answer 1

Answer:

$x=\sqrt{2}$  and   $x=\frac{5\sqrt{2} }{4}$

Step-by-step explanation:

$2\sqrt{2} x^{2} -9x+5\sqrt{2}$

$=2\sqrt{2} x^{2} -5x-4x+5\sqrt{2}$                 ....($2\sqrt{2}*5\sqrt{2} =10*2=20$)

=$x(2\sqrt{2} x-5)-\sqrt{2} (2\sqrt{2}x -5)$

$=(x-\sqrt{2} )(2\sqrt{2} x-5)$

$x-\sqrt{2} =0$           $2\sqrt{2}x-5=0$            

$x=\sqrt{2}$                $x=\frac{5}{2\sqrt{2} }$

                           $x=\frac{5}{2\sqrt{2} } *\frac{2\sqrt{2} }{2\sqrt{2} }$

                           $x=\frac{10\sqrt{2} }{8}$

                          $x=\frac{5\sqrt{2} }{4}$